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What speed must the Death Star go in order to orbit at 1,226.136 km?

$\frac{Gm}{r^2}=a_g\:\:\:\:\:\:\:\frac{\:\:v^2}{r}=a_c\:\:\:\:\:\:\:\:\:\:\:\frac{Gm}{r^2}=\frac{v^2}{r}$

$\frac{\left(6.67e^{-11}m^3kg^{-1}s^{-2}\cdot5.97e^{24}kg\right)}{\left(1,226.136km+6,378.1km\right)\cdot1000m}=v^2\:\:\:\:\:so\:\:\:\:\:\:v=7,236.395\frac{m}{s}$

If the Death Star were just a point in space, it would only take 12 hours and 42 minutes to get to get there if you traveled upwards at 60 mph!

The Death Star's maximum radius could only be 1217.288 km, because anything higher than that would cause it to crash into Mount Everest. If it had that radius, it would be only 8.848 km above the Earth's surface, and it would only take about 5 minutes and 30 seconds to reach the Death Star if you were traveling 60 mph upwards.

What would Derrick Rose's gravitational constant be if the Death Star was on the exact opposite side of the earth? o-<(earth) (DS)

$-9.8\frac{m}{s}-\frac{Gm}{r^2}=\:g$

$-9.8\frac{m}{s^2}-.0251\frac{m}{s^2}=-9.8251\frac{m}{s^2}$

Wow, so if the Death Star is on the other side of the Earth, it doesn't even do that much! Maybe it would be cool to have one orbiting the earth, other than the issues with the tides and the threat of imminent doom.

That's all, folks! Thanks for watching!

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[{:content=>"What speed must the Death Star go in order to orbit at 1,226.136 km?\n<img class=\"equation_image\" title=\"\\frac{Gm}{r^2}=a_g\\:\\:\\:\\:\\:\\:\\:\\frac{\\:\\:v^2}{r}=a_c\\:\\:\\:\\:\\:\\:\\:\\:\\:\\:\\:\\frac{Gm}{r^2}=\\frac{v^2}{r}\" src=\"/equation_images/%255Cfrac%257BGm%257D%257Br%255E2%257D%253Da_g%255C%253A%255C%253A%255C%253A%255C%253A%255C%253A%255C%253A%255C%253A%255Cfrac%257B%255C%253A%255C%253Av%255E2%257D%257Br%257D%253Da_c%255C%253A%255C%253A%255C%253A%255C%253A%255C%253A%255C%253A%255C%253A%255C%253A%255C%253A%255C%253A%255C%253A%255Cfrac%257BGm%257D%257Br%255E2%257D%253D%255Cfrac%257Bv%255E2%257D%257Br%257D\" alt=\"\\frac{Gm}{r^2}=a_g\\:\\:\\:\\:\\:\\:\\:\\frac{\\:\\:v^2}{r}=a_c\\:\\:\\:\\:\\:\\:\\:\\:\\:\\:\\:\\frac{Gm}{r^2}=\\frac{v^2}{r}\">\n<img class=\"equation_image\" title=\"\\frac{\\left(6.67e^{-11}m^3kg^{-1}s^{-2}\\cdot5.97e^{24}kg\\right)}{\\left(1,226.136km+6,378.1km\\right)\\cdot1000m}=v^2\\:\\:\\:\\:\\:so\\:\\:\\:\\:\\:\\:v=7,236.395\\frac{m}{s}\" src=\"/equation_images/%255Cfrac%257B%255Cleft%25286.67e%255E%257B-11%257Dm%255E3kg%255E%257B-1%257Ds%255E%257B-2%257D%255Ccdot5.97e%255E%257B24%257Dkg%255Cright%2529%257D%257B%255Cleft%25281%252C226.136km%2B6%252C378.1km%255Cright%2529%255Ccdot1000m%257D%253Dv%255E2%255C%253A%255C%253A%255C%253A%255C%253A%255C%253Aso%255C%253A%255C%253A%255C%253A%255C%253A%255C%253A%255C%253Av%253D7%252C236.395%255Cfrac%257Bm%257D%257Bs%257D\" alt=\"\\frac{\\left(6.67e^{-11}m^3kg^{-1}s^{-2}\\cdot5.97e^{24}kg\\right)}{\\left(1,226.136km+6,378.1km\\right)\\cdot1000m}=v^2\\:\\:\\:\\:\\:so\\:\\:\\:\\:\\:\\:v=7,236.395\\frac{m}{s}\">\n \nIf the Death Star were just a point in space, it would only take 12 hours and 42 minutes to get to get there if you traveled upwards at 60 mph!\nThe Death Star's maximum radius could only be 1217.288 km, because anything higher than that would cause it to crash into Mount Everest. If it had that radius, it would be only 8.848 km above the Earth's surface, and it would only take about 5 minutes and 30 seconds to reach the Death Star if you were traveling 60 mph upwards.\n \nWhat would Derrick Rose's gravitational constant be if the Death Star was on the exact opposite side of the earth?    o-&lt;(earth)  (DS)\n<img class=\"equation_image\" title=\"-9.8\\frac{m}{s}-\\frac{Gm}{r^2}=\\:g\" src=\"/equation_images/-9.8%255Cfrac%257Bm%257D%257Bs%257D-%255Cfrac%257BGm%257D%257Br%255E2%257D%253D%255C%253Ag\" alt=\"-9.8\\frac{m}{s}-\\frac{Gm}{r^2}=\\:g\">\n<img class=\"equation_image\" title=\"-9.8\\frac{m}{s^2}-.0251\\frac{m}{s^2}=-9.8251\\frac{m}{s^2}\" src=\"/equation_images/-9.8%255Cfrac%257Bm%257D%257Bs%255E2%257D-.0251%255Cfrac%257Bm%257D%257Bs%255E2%257D%253D-9.8251%255Cfrac%257Bm%257D%257Bs%255E2%257D\" alt=\"-9.8\\frac{m}{s^2}-.0251\\frac{m}{s^2}=-9.8251\\frac{m}{s^2}\">\n \nWow, so if the Death Star is on the other side of the Earth, it doesn't even do that much! Maybe it would be cool to have one orbiting the earth, other than the issues with the tides and the threat of imminent doom.\n \nThat's all, folks! Thanks for watching!", :section_type=>"rich_text"}, {:attachment_id=>24418233, :section_type=>"attachment"}]

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