DATA MEASURED:

Trial:	V(volts)	R(m)	I(Amps)
1	122.3	.0055	2.8
2	122.3	.007	1.87
3	122.3	.0095	1.84
4	239.0	.0055	2.72
5	239.0	.007	1.53
6	239.0	.0095	1.13

 

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Electric Field Values:

 

We must use the equation,

Knowing: 

               

 

For example:

 

  

 

Trial	B Value
1	.0127
2	.0085
3	.0083
4	.0124
5	.0070
6	.0051

 

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 Velocity of Electrons:

 

Before Calculating, the necessary equation must be derived from the following two:

1) ()

This equation equates the kinetic energy gained to the energy added from the electron passing across a potential difference

2)

This equation provides the charge to mass ratio in terms the strength of the electric field, its velocity, and the radius of the path it took.

 

We First solve eq. 2 for the mass:

And proceed to substitute it directly into equation 1:

Solving for the velocity of the particle, we obtain the result:

For example:

 

Trial	v(m/s)
1	3.502*10^6
2	4.111*10^6
3	3.102*10^6
4	7.009*10^6
5	9.755*10^6
6	9.866*10^6

 

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Mass Calculation:

 

The final piece of the puzzle uses the charge to mass ratio equation we used earlier

But we must first solve it for mass

 

Now we have all of the necessary data to calculate masses, because we already know the charge of an electron (1.602*10^-19 C)

 

Substituting all of our data for trial 1 yields:

 

Trial	Mass
1	3.195*10^-30
2	2.319*10^-30
3	4.072*10^-30
4	1.559*10^-30
5	8.047*10^-31
6	7.867*10^-31

 

Average Mass: 

Actual Mass: 

 

 

Percent Error: 

Percent Error: 

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